How mass of an electron can be obtained ?
An electron beam is moving between two parallel plates having electric field $1.125 \times {10^{ - 6}}N/m$. A magnetic field $3 \times {10^{ - 10}}T$ is also applied so that beam of electrons do not deflect. The velocity of the electron is ............ $m/s$
Cathode rays are similar to visible light rays in that
Order of q/m ratio of proton, $\alpha $ -particle and electron is
In the Millikan's experiment, the distance between two horizontal plates is $2.5 \,\,cm$ and the potential difference applied is $250\,\, V$ . The electric field between the plates will be ....... $V/m$
An $\alpha$ particle is accelerated through a p.d of ${10^6}$ volt then $ K.E$ . of particle will be .......... $MeV$